Perfect numbers

eguzman2 07 Oct 2008 00:28

I found a formula to find the first seven consecutive perfect numbers which is (2^(x-1))*(2^x - 1), where x is a natural number. So we have the following:

6 = (2)(3) = (2^(2-1))*(2^2 - 1)

28 = (4)(7) = (2^(3-1))*(2^3 - 1)

496 = (16)(31) = (2^(5-1))*(2^5 - 1)

8,128 = (64)(127) = (2^(7-1))*(2^7 - 1)

33,550,336 = (4096)(8191) = (2^(13-1))*(2^13 - 1)

8,589,869,056 = (65536)(131071) = (2^(17-1))*(2^17 - 1)

137,438,691,328 = (262144)(524287) = (2^(19-1))*(2^19 - 1)

Here is the link where I found the formula Perfect Numbers. There is also information on perfect odds.